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1. T man :sex: :puffgiga: :puffpowerroll: (epic music enjoyer) (theorytoe@ak.kyaruc.moe)'s status on Monday, 13-Nov-2023 11:24:23 JST T man :sex: :puffgiga: :puffpowerroll: (epic music enjoyer)

   in reply to
   @meso @lizzie @hidden @dushman
   
   so ax^2+bx+c=0 is standard form of a quadratic, its usually how they are presented to you
   
   x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a} is the general derivation for any given quadratic. if you plug in the vars for a,b,and c (referencing the standard form) and compute for both +/- (\pm in the formula) you will get a solution for each. (the D is the descriminant but i dont remember that that much so someone else can do the talking for me)
   
   the reason why you have 2 solutions is that when you step through and compute the values of x (given a decent range of iteration) as long as the range is not greater than one, you will have either 1 or 2 solutions (ie when x=0) if its greater than 1 you get 1 or two imaginary solutions (ie not on the standard 2d plane)